document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1073461>Question 1073461</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me solve this problem? In a country, deforestation occurs at the rate of about 4.1% per year. Assume that the amount of forest remaining is determined by the function <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+F+=+Fo+%2A+e+%5E%28-0.041t%29+ ALIGN=MIDDLE  ALT=\"+F+=+Fo+%2A+e+%5E%28-0.041t%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >, where Fo is the present acreage of forest land and t is the time in years from the present. In how many years will there be only 60% of the present acreage remaining? Hint: Find the amount of time it takes for Fo to become 0.06Fo. I'm not sure how to start this problem off.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #688293 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=688293\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Can you please help me solve this problem? In a country, deforestation occurs at the rate of about 4.1% per year. Assume that the amount of forest remaining is determined by the function <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+F+=+Fo+%2A+e+%5E%28-0.041t%29+ ALIGN=MIDDLE  ALT=\"+F+=+Fo+%2A+e+%5E%28-0.041t%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >, where Fo is the present acreage of forest land and t is the time in years from the present. In how many years will there be only 60% of the present acreage remaining? Hint: Find the amount of time it takes for Fo to become 0.06Fo. I'm not sure how to start this problem off. <BR>\n" );
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document.write( "So yes, that is close, except 60% is 0.60 (not 0.06).\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+F+=+0.60Fo+=+Fo%2Ae%5E%28-0.041t%29+ ALIGN=MIDDLE  ALT=\"+F+=+0.60Fo+=+Fo%2Ae%5E%28-0.041t%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+++++++0.60+=+e%5E%28-0.041t%29+ ALIGN=MIDDLE  ALT=\"+++++++0.60+=+e%5E%28-0.041t%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >      <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+++ln%280.60%29+=+-0.041t+ ALIGN=MIDDLE  ALT=\"+++ln%280.60%29+=+-0.041t+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "You'll just need to solve for t from here...<BR>\n" );
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