document.write( "Question 1073416: One solution of alcohol is 30% and a second is 60% alcohol. How much of each should be mixed in order to make 90 liters of a solution that is 50% alcohol? \n" ); document.write( "
Algebra.Com's Answer #688244 by josgarithmetic(39618)\"\" \"About 
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x, amount of 30%
\n" ); document.write( "90-x, amount of 60%\r
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\n" ); document.write( "\n" ); document.write( "\"%2830x%2B60%2890-x%29%29%2F90=50\"\r
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\n" ); document.write( "\n" ); document.write( "-
\n" ); document.write( "\"3x%2B6%2890-x%29=9%2A50\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B2%2890-x%29=3%2A50\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B180-2x=150\"\r
\n" ); document.write( "\n" ); document.write( "\"-x=150-180\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=30%29\" ----------volume of the 30%
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\n" ); document.write( "\"highlight%2890-x=60%29\"---------volume of the 60%
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