document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1073416>Question 1073416</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One solution of alcohol is 30% and a second is 60% alcohol. How much of each should be mixed in order to make 90 liters of a solution that is 50% alcohol? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #688243 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=688243\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the amount of 60% alcohol. Then the amount of 30% alcohol would be 90-n. So:<BR>\n" );
document.write( ".6n+.3(90-n)=.5(90)<BR>\n" );
document.write( ".3n+27=45<BR>\n" );
document.write( ".3n=18<BR>\n" );
document.write( "n=60<BR>\n" );
document.write( "60 liters of .6 alcohol and 30 liters of .3 alcohol will give you the desired mixture. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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