document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1060437>Question 1060437</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 25 to the power of 10x+8=(1/125) to the power of 4-2x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #688229 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=688229\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 25^(10x+8)=(1/125)^(4-2x)<BR>\n" );
document.write( "(5^2)^(10x+8)=(5^-3)^4-2x<BR>\n" );
document.write( "5^(20x+16)=5^(-12+6x)<BR>\n" );
document.write( "20x+16=6x-12<BR>\n" );
document.write( "14x=-28<BR>\n" );
document.write( "x=-2. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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