document.write( "Question 1073333: Given the following equation, determine if the following symmetry exists.
\n" ); document.write( "f(x)=-2x^3+4x^2-2x+1
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\n" ); document.write( "1. x- axis
\n" ); document.write( "2. y=x
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Algebra.Com's Answer #688190 by KMST(5328)\"\" \"About 
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Neither
\n" ); document.write( "1. For the graph of a relation to be symmetrical with respect to the x-axis,for every point (x,y), its reflection over the x-axis, point (X,-Y) must also be in the graph.
\n" ); document.write( "That means that changing y to -y, you get the same equation.
\n" ); document.write( "That cannot happen with a function,
\n" ); document.write( "because by definition a function assigns just one y value to every x.
\n" ); document.write( "It cannot assign y and -y for the same x.
\n" ); document.write( "2. I assume that means symmetry about the y=x line.
\n" ); document.write( "For that symmetry, if a point (x,y) is part of the graph, (y,x) must be part of the graph too.
\n" ); document.write( "That means that swapping the x and y variables you get the same equation.
\n" ); document.write( "Some functions could do that, but the only polynomial that can do that is the degree 1 polynomial f(x)=x or y=x.
\n" ); document.write( "If one of the variables has an exponent that the other does not have,
\n" ); document.write( "swapping variables cannot possibly yield the same equation.
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\n" ); document.write( "\"f%28x%29=-2x%5E3%2B4x%5E2-2x%2B1\" is a polynomial in \"x\" .
\n" ); document.write( "Polynomials in \"x\" have graphs like
\n" ); document.write( "\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C0.05%28x%2B5%29%28x-1%29%28x-3%29%2B1%29\" and \"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C0.05%28x%2B5%29%28x%2B1%29%28x-2%29%28x-6%29%29\" .
\n" ); document.write( "With any luck,
\n" ); document.write( "a polynomial of even degree may be symmetrical with respect to the y-axis,
\n" ); document.write( "or a polynomial of odd degree may be symmetrical about the origin.
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