document.write( "Question 1073252: in the incoming year, the probability is 0.30 that the price of a certain house will go up 20%, the probability is 0.50 that the price will go up 10%, the probability is 0.10 that the price will remain the same, and the probability is 0.10 that the price will go down 10%. find the expected percentage increase.\r
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Algebra.Com's Answer #688100 by Theo(13342)\"\" \"About 
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.3 * 20% + .5 * 10% + .1 * 0% + .1 * -10% = 10%\r
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\n" ); document.write( "\n" ); document.write( "the expected percentage increase is 10%.\r
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\n" ); document.write( "\n" ); document.write( "you can also calculate the expected percent increase as follows:\r
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\n" ); document.write( "\n" ); document.write( "assume the value of the investment is x.\r
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\n" ); document.write( "\n" ); document.write( "30% of the time it will increase 20% to become 1.2 * x
\n" ); document.write( "50% of the time it will increase 10% to become 1.1 * x
\n" ); document.write( "10% of the time it will increase 0% to become 1.0 * x
\n" ); document.write( "10% of the time it will decrease 10% to become .9 * x\r
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\n" ); document.write( "\n" ); document.write( "expected value of the investment becomes:\r
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\n" ); document.write( "\n" ); document.write( ".3 * (1.2 * x) + .5 * (1.1 * x) + .1 * (1.0 * x) + .1 * (.9 * x)\r
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\n" ); document.write( "\n" ); document.write( "you will get expected value = 1.1 * x.\r
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\n" ); document.write( "\n" ); document.write( "the percent increase in value is 1.1 * x / 1.0 * x = .1.\r
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\n" ); document.write( "\n" ); document.write( "multiply that by 100 and it becomes 10%.\r
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