document.write( "Question 1073227: part of $3000 is invested at 12% another part at 13% and the remainder at 14% yearly interest. the total yearly income from the three investments is $400. the sum of the amounts invested at 12%and 13% equals the amount invested at 14% how much is invested at each rate \n" ); document.write( "

Algebra.Com's Answer #688070 by jorel1380(3719) $\"\"$ $\"About$

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Let n be the amount invested at 12%, and be the amount invested at 13%. Then the amount invested at 14% would be n+m. So:
\n" ); document.write( "n+m+(n+m)=3000
\n" ); document.write( ".12n+.13m+.14(n+m)=400
\n" ); document.write( "------------------
\n" ); document.write( "2n+2m=3000
\n" ); document.write( ".26n+.27m=400
\n" ); document.write( ".26n+.26m=3000*.13=390
\n" ); document.write( ".01m=10
\n" ); document.write( "m=1000
\n" ); document.write( "n=500
\n" ); document.write( "m+n=1500
\n" ); document.write( "$500 was invested at 12%, $1000 was invested at 13%, and $1500 was invested at 14%. ☺☺☺☺
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