document.write( "Question 94491: You have 40 gallons of 20% solution. How Much 8% soultion do you need to add to get some 12% solution? How much solution will you have then? \n" ); document.write( "
Algebra.Com's Answer #68807 by checkley71(8403)\"\" \"About 
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.2*40+.08X=.12(40+X)
\n" ); document.write( "8+.08X=4.8+.12X
\n" ); document.write( ".08X-.12X=4.8-8
\n" ); document.write( "-.04X=-3.2
\n" ); document.write( "X=-3.2/.04
\n" ); document.write( "X=80 GALLONS OF 8% SOLUTION IS REQUIRED.
\n" ); document.write( "PROOF
\n" ); document.write( ".2*40+.08*80=.12(40+80)
\n" ); document.write( "8+6.4=.12*120
\n" ); document.write( "14.4=14.4
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