document.write( "Question 1073138: Two train stations are 1250 km apart. At midnight, a passenger train and a freight train leave these stations and start towards each other. The passenger train travels 30km/h faster than the freight train, but the passenger train stops for one hour while the freight train travels non-stop. The two trains pass each other at 5:00. Find the rate of each train. \n" ); document.write( "
Algebra.Com's Answer #688041 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Two train stations are 1250 km apart. At midnight, a passenger train and a freight train leave these stations and start towards each other. \n" ); document.write( " The passenger train travels 30km/h faster than the freight train, but the passenger train stops for one hour while the freight train travels non-stop. \n" ); document.write( " The two trains pass each other at 5:00. Find the rate of each train. \n" ); document.write( "; \n" ); document.write( "I am ashamed to say that I made a stupid math mistake. Here is the corrected version of this problem \n" ); document.write( ": \n" ); document.write( "let's assume the passenger train stops for 1 hr before they meet \n" ); document.write( "then the passenger travel time = 4 hrs, the freight travels 5 hrs \n" ); document.write( "let s = speed of the freight \n" ); document.write( "then \n" ); document.write( "(s+30) = the speed of the passenger train \n" ); document.write( "The sum of their distances will be 1250 km \n" ); document.write( "4(s+30) + 5s = 1250 \n" ); document.write( "4s + 120 + 5s = 1250 \n" ); document.write( "9s = 1250 - 120 \n" ); document.write( "9s = 1130 \n" ); document.write( "s = 1130/9 \n" ); document.write( "s = 125.6 km/hr is the speed of the freight \n" ); document.write( "then \n" ); document.write( "125.6 + 30 = 155.6 km/hr is the speed of the passenger train \n" ); document.write( ": \n" ); document.write( "Now let's assume the passenger train stops for 1 hr after they meet \n" ); document.write( "then both the passenger and the freight travel for 5 hrs \n" ); document.write( "let s = speed of the freight \n" ); document.write( "then \n" ); document.write( "(s+30) = the speed of the passenger train \n" ); document.write( "The sum of their distances will be 1250 km \n" ); document.write( "5(s+30) + 5s = 1250 \n" ); document.write( "5s + 150 + 5s = 1250 \n" ); document.write( "10s = 1250 - 150 \n" ); document.write( "10s = 1100 \n" ); document.write( "s = 1100/10 \n" ); document.write( "s = 110 km/hr is the speed of the freight \n" ); document.write( "then \n" ); document.write( "110 + 30 = 140 km/hr is the speed of the passenger train \n" ); document.write( " |