document.write( "Question 1073151: Using y2 -4y -4x = 0, Find the vertex, the focus, and the directrix then graph the equation \n" ); document.write( "
Algebra.Com's Answer #688026 by josgarithmetic(39620)\"\" \"About 
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\"y%5E2-4y-4x=0\"
\n" ); document.write( "\"4x=y%5E2-4y\"
\n" ); document.write( "\"4x=y%5E2-4y%2B4-4\"
\n" ); document.write( "\"4x=%28y-2%29%5E2-4\"
\n" ); document.write( "\"4x%2B4=%28y-2%29%5E2\"
\n" ); document.write( "\"highlight%284%28x%2B1%29=%28y-2%29%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Vertex is the left-most point, and the parabola opens toward the right. Symmetry axis is parallel to the x-axis.\r
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\n" ); document.write( "\n" ); document.write( "Equation indicates vertex (-1,2).\r
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\n" ); document.write( "\n" ); document.write( "The factor 4 on the left indicates that some distance p so that 4p=4, is how far both the directrix and focus are from the vertex. Here, p=1. \r
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\n" ); document.write( "\n" ); document.write( "DIRECTRIX: \"x=-2\"
\n" ); document.write( "FOCUS: (0,2)\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-2%2C8%2C-3%2C7%2C2-2sqrt%28x%2B1%29%2C2%2B2sqrt%28x%2B1%29%29\"
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