document.write( "Question 1073007: Using Euler's formula of ea + bi = ea(cos b + i sin b), derive the arisen equation of eπi + 1 = 0 \n" ); document.write( "

Algebra.Com's Answer #687952 by MaxWong(38) $\"\"$ $\"About$

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e^(a+bi) = e^a(cos b + i sin b)\r
\n" ); document.write( "\n" ); document.write( "Therefore e^(pi*i) = cos pi + i sin pi = -1 + 0i = -1.\r
\n" ); document.write( "\n" ); document.write( "e^πi + 1 = 0
\n" ); document.write( "e^πi = -1\r
\n" ); document.write( "\n" ); document.write( "The results match :D \n" ); document.write( "

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