document.write( "Question 1073026: Latisha wants a average of 86% in history class. Her past scores are 90%, 82%, 81%. If this test is double points. What percent does she need to get a average of 86%? On my homework help it says divide the number by 5 but I think it should be 4 since there is 4 tests. I have tried guessing and checking and I am truly puzzled. Please help! :) \n" ); document.write( "
Algebra.Com's Answer #687881 by ankor@dixie-net.com(22740)\"\" \"About 
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Latisha wants a average of 86% in history class.
\n" ); document.write( " Her past scores are 90%, 82%, 81%.
\n" ); document.write( " If this test is double points.
\n" ); document.write( " What percent does she need to get a average of 86%?
\n" ); document.write( ":
\n" ); document.write( "The reason they divide by 5 is because the last test counts \"double\" on her average, therefore we treat it like two test
\n" ); document.write( ":
\n" ); document.write( "let x = the score on the last test
\n" ); document.write( "\"%28%2890+%2B+82+%2B+81+%2B+2x%29%29%2F5\" = 86
\n" ); document.write( "multiply both sides by 5, add up the scores
\n" ); document.write( "253 + 2x = 5(86)
\n" ); document.write( "2x = 430 - 253
\n" ); document.write( "2x = 177
\n" ); document.write( "x = 177/2
\n" ); document.write( "x = 88.5 would give her a 86% average\r
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