document.write( "Question 94408: sally bought three chocolate bars and a pack of gum and paid 41.75. jAKE BOUGHT TWO chocolate bars and four packs of gum and paid $2.00. Find the cost of a chocolate bar and the cost of a pack of gum. BRAIN FRIED \n" ); document.write( "
Algebra.Com's Answer #68783 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The first statement has an obvious mistake. Changed 41.75 to 1.75\r
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\n" ); document.write( "\n" ); document.write( "Let x = price of choc bars, and y = price of gum
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\n" ); document.write( "Write an equation representing each statement, we will use elimination:
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\n" ); document.write( "\"sally bought three chocolate bars and a pack of gum and paid 1.75.\"
\n" ); document.write( " 3x + 1y = 1.75
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\n" ); document.write( "\"jAKE BOUGHT TWO chocolate bars and four packs of gum and paid $2.00.\"
\n" ); document.write( " 2x + 4y = 2.00
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\n" ); document.write( " Find the cost of a chocolate bar and the cost of a pack of gum.
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\n" ); document.write( "Multiply the 1st equation by 4 and subtract the 2nd equation from it:
\n" ); document.write( " 12x + 4y = 7.00
\n" ); document.write( " 2x + 4y = 2.00
\n" ); document.write( "------------------- subtracting eliminates y, find x.
\n" ); document.write( " 10x + 0y = 5.00
\n" ); document.write( " x = 5.00/10
\n" ); document.write( " x = .50 for a chocolate bar
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\n" ); document.write( "Find y using the 1st equation, substitute .50 for x
\n" ); document.write( "3(.50) + 1y = 1.75
\n" ); document.write( " 1.50 + 1y = 1.75
\n" ); document.write( " y = 1.75 - 1.50
\n" ); document.write( " y = .25 for gum
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\n" ); document.write( "Check our solutions in the 2nd equation:
\n" ); document.write( "2(.50) + 4(.25) =
\n" ); document.write( "1.00 + 1.00 = 2.00
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\n" ); document.write( "How about this, has your brain recovered somewhat? Any questions?\r
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