document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1072906>Question 1072906</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For three weeks in December your boss holds a lottery to receive an extra day off for the holidays.  You and 9 other employees are entered each week and one name is chosen at random (you can win more than once).  What is the probability that you win at least one time? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #687740 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=687740\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's look at the possibility of NOT being chosen. That would be (8/9)^3, since the lottery is being held for three weeks. This amounts to 0.702331961591220850480109739369. Now we take this and subtract it from 1, which gives us 0.297668038408779149519890260631, or a 29.7668% chance of being picked at least once. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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