document.write( "Question 1072831: Please help me understand this problem,The length of a rectangular court of badminton is 27 feet longer than its width. If its perimeter is 122 feet. What are the dimensions of the rectangular court? Thank you :) \n" ); document.write( "
Algebra.Com's Answer #687675 by ikleyn(52797)\"\" \"About 
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document.write( "Let L be the length, W be the width, in feet.\r\n" );
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document.write( "The condition says  L = W + 27.\r\n" );
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document.write( "It also says about the perimeter\r\n" );
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document.write( "L + W + L + W = 122.\r\n" );
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document.write( "Replace here L by (W + 27). You will get\r\n" );
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document.write( "(W+27) + W + (W+27) + W = 122,  or\r\n" );
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document.write( "4W + 54 = 122  ---->  4W = 122 - 54 = 68  --->  W = 68/4 = 17.\r\n" );
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document.write( "Answer.  The width of the court is 17 ft. The length is 17+ 27 = 44 ft.\r\n" );
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document.write( "Check.  44 + 17 + 44 + 17 = 122.  Correct !\r\n" );
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