document.write( "Question 1072764: A total of
\n" ); document.write( "$7000 is invested: part at
\n" ); document.write( "7% and the remainder at
\n" ); document.write( "12%
\n" ); document.write( ".
\n" ); document.write( "How much is invested at each rate if the annual interest is
\n" ); document.write( "$650
\n" ); document.write( "?
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Algebra.Com's Answer #687614 by jorel1380(3719)\"\" \"About 
You can put this solution on YOUR website!
Let n be the amount invested at 12%. Then the amount invested at 7% is 7000-n. So:
\n" ); document.write( ".12n+.07(7000-n)=650
\n" ); document.write( ".05n=160
\n" ); document.write( "n=3200
\n" ); document.write( "$3200 is invested at 12%, and $3800 is invested at 7%. ☺☺☺☺
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