document.write( "Question 1072764: A total of
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document.write( "$7000 is invested: part at
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document.write( "7% and the remainder at
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document.write( "12%
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document.write( "How much is invested at each rate if the annual interest is
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document.write( "$650
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document.write( "? \n" );
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Algebra.Com's Answer #687614 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! Let n be the amount invested at 12%. Then the amount invested at 7% is 7000-n. So: \n" ); document.write( ".12n+.07(7000-n)=650 \n" ); document.write( ".05n=160 \n" ); document.write( "n=3200 \n" ); document.write( "$3200 is invested at 12%, and $3800 is invested at 7%. ☺☺☺☺ \n" ); document.write( " |