document.write( "Question 1072771: At 09 00, car A started its journey and travelled at 70km/h. At 10 30, car B started from the same place and travelled steadily on the same road. Car B took 3 1/2 h to catch up to car A.\r
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document.write( "a) Find the speed of car B
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document.write( "b) At 15 24, car B reached its destination. When did car A reach the same destination? \n" );
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Algebra.Com's Answer #687604 by josgarithmetic(39616)![]() ![]() ![]() You can put this solution on YOUR website! Amount of time between 9:00 and 10:30 is \n" ); document.write( "\n" ); document.write( "Doing part (a) only: \n" ); document.write( " \r\n" ); document.write( "CAR SPEED TIME DISTANCE\r\n" ); document.write( "\r\n" ); document.write( "A 70\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "- \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |