document.write( "Question 1072771: At 09 00, car A started its journey and travelled at 70km/h. At 10 30, car B started from the same place and travelled steadily on the same road. Car B took 3 1/2 h to catch up to car A.\r
\n" ); document.write( "\n" ); document.write( "a) Find the speed of car B
\n" ); document.write( "b) At 15 24, car B reached its destination. When did car A reach the same destination?
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Algebra.Com's Answer #687604 by josgarithmetic(39616)\"\" \"About 
You can put this solution on YOUR website!
Amount of time between 9:00 and 10:30 is \"1%261%2F2\" hours.\r
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document.write( "CAR      SPEED         TIME           DISTANCE\r\n" );
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document.write( "A         70          \"1%261%2F2%2B3%261%2F2\"      d\r\n" );
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document.write( "B          r           \"3%261%2F2\"           d\r\n" );
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\n" ); document.write( "\n" ); document.write( "\"70%281%261%2F2%2B3%261%2F2%29=%283%261%2F2%29%2Ar\"\r
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\n" ); document.write( "\n" ); document.write( "-
\n" ); document.write( "\"70%2A5=%287%2F2%29r\"\r
\n" ); document.write( "\n" ); document.write( "\"r=70%2A5%2A%282%2F7%29\"\r
\n" ); document.write( "\n" ); document.write( "\"r=10%2A5%2A2\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28r=100%29\"
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