document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1072608>Question 1072608</A>: <I><SPAN STYLE=\"word-break: break-all;\"> . How long will it take for a sum of money to triple in value if invested at an annual rate of 3% compounded continuously? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #687573 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=687573\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the initial amount. Then 3n would be:<BR>\n" );
document.write( "3=e^.03t(where t is the time) <BR>\n" );
document.write( "So:<BR>\n" );
document.write( "log 3=log e^.03t<BR>\n" );
document.write( "log 3=.03t(log e)<BR>\n" );
document.write( "t=log 3/.03 log e<BR>\n" );
document.write( "t=36.62 years before the money triples. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );