document.write( "Question 94401: A bus leaves a station at 1PM, traveling west at an average rate of 44 mile per hour. One hour later a second bus leaves the same station, traveling east at a rate of 48 mile per hour. At what time will the two buses be 274 miles apart?\r
\n" ); document.write( "\n" ); document.write( "What formula should I use to find the exact answer? Just by manually adding it up I got the two would be at that distance around 4:32, but I don't know how to get to that answer with a formula. \n" ); document.write( "
Algebra.Com's Answer #68757 by ankor@dixie-net.com(22740)\"\" \"About 
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A bus leaves a station at 1PM, traveling west at an average rate of 44 mile per hour. One hour later a second bus leaves the same station, traveling east at a rate of 48 mile per hour. At what time will the two buses be 274 miles apart?
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\n" ); document.write( "Let t = travel time of the westbound bus, which left at 1pm
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\n" ); document.write( "(t-1) = travel time of the eastbound bus, which left at 2pm
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\n" ); document.write( "Write a distance equation: Dist = speed * time
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\n" ); document.write( "W.Bus dist + E.Bus dist = 274
\n" ); document.write( "44t + 48(t-1) = 274
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\n" ); document.write( "44t + 48t - 48 = 274
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\n" ); document.write( "92t = 274 + 48
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\n" ); document.write( "t = 322/92
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\n" ); document.write( "t = 3.5 hrs + 1 pm = 4:30 PM when they are 274 mi apart
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\n" ); document.write( "Check solution:
\n" ); document.write( "44(3.5) + 48(2.5) = 274
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