document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1072615>Question 1072615</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Miguel's coin collection consists of dimes and quarters. If he has 53 coins that are worth $7.85, how many of each type of coin does he have?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #687566 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=687566\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let d be the amount of dimes in the collection; and q be the amount of quarters. Then:<BR>\n" );
document.write( "d+q=53<BR>\n" );
document.write( "d=53-q<BR>\n" );
document.write( "So:<BR>\n" );
document.write( "25q+10(53-q)=785<BR>\n" );
document.write( "15q+530=785<BR>\n" );
document.write( "15q=255<BR>\n" );
document.write( "q=17<BR>\n" );
document.write( "d=36<BR>\n" );
document.write( "There are 17 quarters and 36 dimes in the collection. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );