document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1072674>Question 1072674</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A couple bought some stock for $30 per share that pays an annual dividend of $1.80 per share. After 1 year the price of the stock was $33. Find the simple interest rate on the growth of their investment.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #687563 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=687563\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The initial price of the stock is $30. Then the growth of their investment would be:<BR>\n" );
document.write( "33/30=1.1<BR>\n" );
document.write( "1.1-1=.1, or 10% growth on their stock. \r<BR>\n" );
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document.write( "If you count the dividend as growth, then you have:<BR>\n" );
document.write( "33+1.8/30=1.16, or 16% growth. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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