document.write( "Question 1072706: 5/3=(1+.04/12)^12t solve for t \n" ); document.write( "

Algebra.Com's Answer #687535 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"5%2F3=%281%2B.04%2F12%29%5E12t\"$
\n" ); document.write( " $\"5%2F3=%28301%2F300%29%5E12t\"$
\n" ); document.write( " $\"12t=log%28%285%2F3%29%29%2Flog%28%28301%2F300%29%29\"$
\n" ); document.write( " $\"t=%281%2F2%29%2A%28log%28%285%2F3%29%29%2Flog%28%28301%2F300%29%29%29\"$
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