document.write( "Question 1072597: F(x)=.5(2^x), G(x)=5x-12\r
\n" ); document.write( "\n" ); document.write( "A) Determine g(f(0)
\n" ); document.write( "I did try this question and got -9.5 is this incorrect?
\n" ); document.write( "B)(f*g)(x)
\n" ); document.write( "I got to 5(2^(5x-12)) I didn't know what to do with the upper numbers.
\n" ); document.write( "h.) Determine f^(-1)(x)
\n" ); document.write( "(-1) is the power and (x) is on the side.
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Algebra.Com's Answer #687523 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"g%28f%29=5f-12=5%280.5%2A2%5E%28x%29%29-12=2%5E%28x%29-12\"
\n" ); document.write( "So then,
\n" ); document.write( "\"g%28f%280%29%29=2%5E%280%29-12=1-12=-11\"
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\n" ); document.write( "\"f%28g%29=0.5%282%5E%285x-12%29%29\"
\n" ); document.write( "Yes, correct.
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\n" ); document.write( "Use x,y nomenclature.
\n" ); document.write( "Substitute x and y and solve for the new y.
\n" ); document.write( "\"y=0.5%282%5Ex%29\"
\n" ); document.write( "\"x=0.5%282%5Ey%29\"
\n" ); document.write( "\"2x=2%5Ey\"
\n" ); document.write( "\"y=log%28%282x%29%29%2Flog%28%282%29%29\"
\n" ); document.write( "\"f%5E%28-1%29%28x%29=log%28%282x%29%29%2Flog%28%282%29%29\"
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