document.write( "Question 94409: Having issues with this problem, can you help?\r
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\n" ); document.write( "\n" ); document.write( "The sum of two numbers is 112. The second is 7 more than 4 times the first. What are the two numbers?
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Algebra.Com's Answer #68752 by praseenakos@yahoo.com(507)\"\" \"About 
You can put this solution on YOUR website!
Question:\r
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\n" ); document.write( "\n" ); document.write( "Assume that the first number = x\r
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\n" ); document.write( "\n" ); document.write( "Four times the first number = 4x\r
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\n" ); document.write( "\n" ); document.write( "7 more than four times the first = 4x + 7\r
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\n" ); document.write( "\n" ); document.write( "Given that The second is 7 more than 4 times the first.....\r
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\n" ); document.write( "\n" ); document.write( "So the second number = 4x + 7\r
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\n" ); document.write( "\n" ); document.write( "Their sum is given as 112\r
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\n" ); document.write( "\n" ); document.write( "so we can write,\r
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\n" ); document.write( "\n" ); document.write( "x + 4x + 7 = 112\r
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\n" ); document.write( "\n" ); document.write( "==> 5x + 7 = 112\r
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\n" ); document.write( "\n" ); document.write( "Subtract 7 from both sides...\r
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\n" ); document.write( "\n" ); document.write( "5x + 7 - 7 = 112 - 7\r
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\n" ); document.write( "\n" ); document.write( "==> 5x = 105\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 5\r
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\n" ); document.write( "\n" ); document.write( "==> \"+5x%2F5+=+105%2F5+\"\r
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\n" ); document.write( "\n" ); document.write( "==> x = 21\r
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\n" ); document.write( "\n" ); document.write( "So the first number is 21\r
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\n" ); document.write( "\n" ); document.write( "Then the second number is 4x + 7 = 4 * 21 + 7 = 84 + 7 = 91\r
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\n" ); document.write( "\n" ); document.write( "So the numbers are 91 and 21.\r
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\n" ); document.write( "\n" ); document.write( "Hope you found the explanation useful.\r
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\n" ); document.write( "\n" ); document.write( "Regards.\r
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\n" ); document.write( "\n" ); document.write( "Praseena.\r
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