document.write( "Question 1072634: Find three consecutive odd positive integers such that five times the sum of all three is 72 more than the product of the first and second integers . \n" ); document.write( "

Algebra.Com's Answer #687478 by josgarithmetic(39617) $\"\"$ $\"About$

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The integers, $\"system%28x-2%2Cx%2Cx%2B2%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"5%28x-2%2Bx%2Bx%2B2%29=72%2B%28x%28x-2%29%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"5%283x%29=x%5E2-2x%2B72\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2-17x%2B72=0\"$ \r
\n" ); document.write( "\n" ); document.write( "Discriminant, $\"289-4%2A72=1\"$ ,.... or,\r
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\n" ); document.write( "\n" ); document.write( " $\"%28x%5E2-17x%2B72%29=highlight_green%28%28x-8%29%28x-9%29=0%29\"$
\n" ); document.write( "and the description specified ODD integers.
\n" ); document.write( " $\"x=9\"$ \r
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\n" ); document.write( "\n" ); document.write( "The consecutive odd positive integers: 7, 9, 11 \n" ); document.write( "

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