document.write( "Question 1072583: Solve for a: 2log5(3a+1)=log5(4)+2log5(2a-1) \n" ); document.write( "
Algebra.Com's Answer #687443 by stanbon(75887)\"\" \"About 
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Solve for a: 2log5(3a+1)=log5(4)+2log5(2a-1)
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\n" ); document.write( "log5(3a+1)^2 - log5(2a-1)^2 = log(4)/log(5)
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\n" ); document.write( "log5[(3a+1)^2/(2a-1)^2] = 0.8614
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\n" ); document.write( "2log5[(3a+1)/(2a-1)] = 0.8614
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\n" ); document.write( "log5[(3a+1)/(2a-1)] = 0.4307
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\n" ); document.write( "3a+1 = 5^0.4307*(2a-1)
\n" ); document.write( "3a+1 = 2(2a-1)
\n" ); document.write( "3a+1 = 4a-2
\n" ); document.write( "a = 3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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