document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1072572>Question 1072572</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The volume of a smaller sphere is 288 cm^3. Find the volume of a sphere who's radius is 3 times that of the smaller sphere. Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #687432 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=687432\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Volume is a function of the cube of the radius.  Triple the radius, and the volume increases 27-fold to <BR>\n" );
document.write( "288*27=7776 cm^3<BR>\n" );
document.write( "Can do it from first principles<BR>\n" );
document.write( "V=(4/3)pi*r^3=288<BR>\n" );
document.write( "216=pi*r^3<BR>\n" );
document.write( "r^3=216/pi=68.75 cm^3<BR>\n" );
document.write( "r=4.097<BR>\n" );
document.write( "Triple the radius is 12.291<BR>\n" );
document.write( "multiply that by (4/3)*pi*r^3=7778 cm^3.  The difference is in the rounding.  The 288 cm^3 is multiplied by 27, and that is the best answer. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );