document.write( "Question 1072552: How many gallons of a \r
\n" ); document.write( "\n" ); document.write( "90​% antifreeze solution must be mixed with \r
\n" ); document.write( "\n" ); document.write( "60 gallons of \r
\n" ); document.write( "\n" ); document.write( "30​% antifreeze to get a mixture that is \r
\n" ); document.write( "\n" ); document.write( "80​% ​antifreeze? Use the​ six-step method.\r
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Algebra.Com's Answer #687419 by Alan3354(69443)\"\" \"About 
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How many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 80% antifreeze?
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\n" ); document.write( "Add G gallons.
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\n" ); document.write( "60*30 + G*90 = (60+G)*80
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