document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1072508>Question 1072508</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello! How can I find the focus and the directrix of the following equation: (y+2)^2=-12(x-5)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #687388 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=687388\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (y+2)^2 = -12(x-5)<BR>\n" );
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document.write( "This is an equation of a parabola in standard form, this parabola opens to the left since p is negative<BR>\n" );
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document.write( "The standard form is<BR>\n" );
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document.write( "( y - k )^2 = 4 * p * ( x - h )<BR>\n" );
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document.write( "The vertex is (h, k) = (5, -2)<BR>\n" );
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document.write( "Note that p = -12 / 4 = -3<BR>\n" );
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document.write( "Focus = (h + p, k) = (5-3, -2) = (2, -2)<BR>\n" );
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document.write( "Directrix is  x = h - p = 5 - (-3) = 8<BR>\n" );
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