document.write( "Question 1072459: The owner of the Rancho Grande has 2952 yd of fencing with which to enclose a rectangular piece of grazing land situated along the straight portion of a river. If fencing is not required along the river, what are the dimensions of the largest area he can enclose?\r
\n" ); document.write( "\n" ); document.write( "shorter side = ?yd
\n" ); document.write( "Longer side = ?yd\r
\n" ); document.write( "\n" ); document.write( "what is the area = ?yd^2
\n" ); document.write( "

Algebra.Com's Answer #687354 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
It helps to draw this.
\n" ); document.write( "two sides are each x
\n" ); document.write( "the one length is 2952-2x
\n" ); document.write( "the area is x(2952-2x)=-2x^2+2952x.
\n" ); document.write( "The derivative of that is -4x+2952.
\n" ); document.write( "Set it equal to 0 and -4x=-2952 and x=738 yds
\n" ); document.write( "2x=1476 yds
\n" ); document.write( "A=1,089,288 yd^2
\n" ); document.write( "That is the typical answer in these questions, where the width is half the length.
\n" ); document.write( "Can check with a very close width and length, like 736 and 1480, the product of which is 1,089,280 yd^2.
\n" ); document.write( "
\n" ); document.write( "
\n" );