document.write( "Question 1072459: The owner of the Rancho Grande has 2952 yd of fencing with which to enclose a rectangular piece of grazing land situated along the straight portion of a river. If fencing is not required along the river, what are the dimensions of the largest area he can enclose?\r
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document.write( "shorter side = ?yd
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document.write( "Longer side = ?yd\r
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document.write( "what is the area = ?yd^2 \n" );
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Algebra.Com's Answer #687354 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! It helps to draw this. \n" ); document.write( "two sides are each x \n" ); document.write( "the one length is 2952-2x \n" ); document.write( "the area is x(2952-2x)=-2x^2+2952x. \n" ); document.write( "The derivative of that is -4x+2952. \n" ); document.write( "Set it equal to 0 and -4x=-2952 and x=738 yds \n" ); document.write( "2x=1476 yds \n" ); document.write( "A=1,089,288 yd^2 \n" ); document.write( "That is the typical answer in these questions, where the width is half the length. \n" ); document.write( "Can check with a very close width and length, like 736 and 1480, the product of which is 1,089,280 yd^2. \n" ); document.write( " \n" ); document.write( " |