document.write( "Question 1072429: 2. A boat, which moves at 11 mph in water without a current, goes 56 miles upstream and 56 back again in 11 hours. Find the speed of the current to the nearest tenth.\r
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Algebra.Com's Answer #687349 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A boat, which moves at 11 mph in water without a current, goes 56 miles upstream and 56 back again in 11 hours. \n" ); document.write( " Find the speed of the current to the nearest tenth. \n" ); document.write( ": \n" ); document.write( "let c = the rate of the current \n" ); document.write( "then \n" ); document.write( "(11-c) = effective speed upstream \n" ); document.write( "and \n" ); document.write( "(11+c) = effective speed downstream \n" ); document.write( ": \n" ); document.write( "Write a time equation. time = dis/speed \n" ); document.write( "up time + down time = 11 hrs \n" ); document.write( " \n" ); document.write( "multiply equation by (11-c)(11+c), cancel the denominators \n" ); document.write( "56(11+c) + 56(11-c) = 11(11+c)(11-c) \n" ); document.write( "distribute and FOIL \n" ); document.write( "616 + 56c + 616 - 56c = 11(121 - c^2) \n" ); document.write( "1232 = 1331 - 11c^2 \n" ); document.write( "11c^2 = 1331 - 1232 \n" ); document.write( "11c^2 = 99 \n" ); document.write( "c^2 = 99/11 \n" ); document.write( "c^2 = 9 \n" ); document.write( "c = \n" ); document.write( "c = 3 mph is the rate of the current \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "Check this by finding the actual time each way \n" ); document.write( "56/8 = 7 hrs \n" ); document.write( "56/14 = 4 hrs \n" ); document.write( "============= \n" ); document.write( "tot time 11 hrs \n" ); document.write( " |