document.write( "Question 1072429: 2. A boat, which moves at 11 mph in water without a current, goes 56 miles upstream and 56 back again in 11 hours. Find the speed of the current to the nearest tenth.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #687349 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A boat, which moves at 11 mph in water without a current, goes 56 miles upstream and 56 back again in 11 hours.
\n" ); document.write( " Find the speed of the current to the nearest tenth.
\n" ); document.write( ":
\n" ); document.write( "let c = the rate of the current
\n" ); document.write( "then
\n" ); document.write( "(11-c) = effective speed upstream
\n" ); document.write( "and
\n" ); document.write( "(11+c) = effective speed downstream
\n" ); document.write( ":
\n" ); document.write( "Write a time equation. time = dis/speed
\n" ); document.write( "up time + down time = 11 hrs
\n" ); document.write( "\"56%2F%28%2811-c%29%29\" + \"56%2F%28%2811%2Bc%29%29\" = 11
\n" ); document.write( "multiply equation by (11-c)(11+c), cancel the denominators
\n" ); document.write( "56(11+c) + 56(11-c) = 11(11+c)(11-c)
\n" ); document.write( "distribute and FOIL
\n" ); document.write( "616 + 56c + 616 - 56c = 11(121 - c^2)
\n" ); document.write( "1232 = 1331 - 11c^2
\n" ); document.write( "11c^2 = 1331 - 1232
\n" ); document.write( "11c^2 = 99
\n" ); document.write( "c^2 = 99/11
\n" ); document.write( "c^2 = 9
\n" ); document.write( "c = \"sqrt%289%29\"
\n" ); document.write( "c = 3 mph is the rate of the current
\n" ); document.write( ":
\n" ); document.write( ";
\n" ); document.write( "Check this by finding the actual time each way
\n" ); document.write( "56/8 = 7 hrs
\n" ); document.write( "56/14 = 4 hrs
\n" ); document.write( "=============
\n" ); document.write( "tot time 11 hrs
\n" ); document.write( "
\n" );