document.write( "Question 1071937: if 80% of all households of a city have a cd player and 37% of them have a SUV and 18% of all households have both a cd player and suv. \r
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document.write( "what is the probability that a randomly selected household has a cd player or a suv? \n" );
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Algebra.Com's Answer #687291 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! 80% have a cd player, and 37% have an SUV, so: \n" ); document.write( "80+37=117. \n" ); document.write( "18% have a cd player AND an SUV, so: \n" ); document.write( "117-18=99 \n" ); document.write( "So, the chance that a randomly selected household has one or the other, or both, is 99%. ☺☺☺☺ \n" ); document.write( " |