document.write( "Question 1072291: Destiny invests $2500 in one account and $900 in an account paying 4 % higher interest. At the end of one year she had earned $274 in interest. At what rates did she invest?
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Algebra.Com's Answer #687284 by jorel1380(3719) $\"\"$ $\"About$

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Let n be the interest rate of the first account. Then the interest rate of the second account is n+.04. So:
\n" ); document.write( "2500(n)+900(n+.04)=274
\n" ); document.write( "2500n+900n+36=274
\n" ); document.write( "3400n=238
\n" ); document.write( "n=.07
\n" ); document.write( "The interest rate on the first account is 7%; the second account is at 11%. ☺☺☺☺ \n" ); document.write( "

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