document.write( "Question 1072249: XYZ Corporation gives each of its employees an aptitude test. The scores on the test are normally distributed with a mean of 77 and a standard deviation of 12. A simple random sample of 26 is taken from a population of 500. What is the probability that the average aptitude test in the sample will be greater than 81.68 (to 4 decimals)? \n" ); document.write( "
Algebra.Com's Answer #687261 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! mean 77, sd 12 \n" ); document.write( "z=(x-mean)/s/sqrt(n) \n" ); document.write( ">=4.68/(12/sqrt(26)=4.68*sqrt (26)/12=1.989 \n" ); document.write( "The probability z>1.989 is 0.0234; note, if you use 1.99, you get 0.0233 \n" ); document.write( " |