document.write( "Question 1072337: expand
\n" ); document.write( "(X^3-1/X^2)^6
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Algebra.Com's Answer #687256 by Boreal(15235)\"\" \"About 
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I will write as x^3-x^(-2) all raised to the 6th power
\n" ); document.write( "The coefficients will be 1,6,15,20,15,6,1
\n" ); document.write( "The first term is x^18
\n" ); document.write( "The second term is 6*x^15*x^(-2)=6x^13
\n" ); document.write( "The third term is 15*(x^12)*x^(-4)=15x^8
\n" ); document.write( "The fourth term is 20(x^9)*x^(-6)=20x^3
\n" ); document.write( "The fifth term is 15 (x^6)*(x^(-8)=15x^(-2)
\n" ); document.write( "The sixth term is 6 (x^3)*(x^(-10)=6/x^7
\n" ); document.write( "the last term is x^(-12)=1/x^12
\n" ); document.write( "the expansion is the sum of all of these.
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