document.write( "Question 1072014: Matt invest $500 into an account with a 7.5% interest rate compounded yearly. How long will it be until the account has a value of $2500? \n" ); document.write( "
Algebra.Com's Answer #687206 by Theo(13342)![]() ![]() You can put this solution on YOUR website! f = p * (1+r) ^ n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f is the future value \n" ); document.write( "p is the present value \n" ); document.write( "r is the interest rate per time period. \n" ); document.write( "n is the number of time periods.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your time period is years.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you are given that:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i = 7.5% per year / 100 = .075 per year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p = 500\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f = 2500\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f = p * (1+r) ^ n becomes 2500 = 500 * 1.075 ^ n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides of this equation by 500 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2500 / 500 = 1.075 ^ n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5 = 1.075 ^ n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "take the log of both sides of this equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(5) = log(1.075 ^ n)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since log(a^b) = b * log(a), your equation becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(5) = n * log(1.075)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides of this equation by log(1.075) to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(5) / log(1.075) = n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for n to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = 22.25419233\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "confirm by replacing n in the original equation and evaluating to see that the equation is true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2500 = 500 * 1.075 ^ n becomes 2500 = 500 * 1.075 ^ 22.25419233.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "evaluate to get 2500 = 2500.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this confirms the solution is good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the solution is that it will take 22.25419233 year for 500 to become 2500 at an interest rate of 7.5% compounded annually.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |