document.write( "Question 94354: I can get the anser to this but I dont know how they got it.v and r are riding their bikes.V rides at 10 miles per hour while R rides at 7.r has a 30 minute head start. How long has R been riding when V is 7 miles ahead of him? \n" ); document.write( "
Algebra.Com's Answer #68716 by edjones(8007) You can put this solution on YOUR website! d=ts \n" ); document.write( "distance=time*speed \n" ); document.write( "for R t=t s=7 d=7t \n" ); document.write( "for V t=t-.5 d=d+7 s=10 \n" ); document.write( "R's distance=V's distance-7 \n" ); document.write( "7t=10(t-.5)-7 \n" ); document.write( "7t=10t-5-7 \n" ); document.write( "7t=10t-12 Then subtract 10t from each side \n" ); document.write( "-3t=-12 then divide both sides by -3 \n" ); document.write( "t=4hrs Time R has been riding when V is 7 mi ahead of him \n" ); document.write( "Check: 4*7=28mi=distance of R \n" ); document.write( "====3.5*10=35mi=distance of V \n" ); document.write( "EdJones \n" ); document.write( " |