document.write( "Question 94354: I can get the anser to this but I dont know how they got it.v and r are riding their bikes.V rides at 10 miles per hour while R rides at 7.r has a 30 minute head start. How long has R been riding when V is 7 miles ahead of him? \n" ); document.write( "
Algebra.Com's Answer #68716 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
d=ts
\n" ); document.write( "distance=time*speed
\n" ); document.write( "for R t=t s=7 d=7t
\n" ); document.write( "for V t=t-.5 d=d+7 s=10
\n" ); document.write( "R's distance=V's distance-7
\n" ); document.write( "7t=10(t-.5)-7
\n" ); document.write( "7t=10t-5-7
\n" ); document.write( "7t=10t-12 Then subtract 10t from each side
\n" ); document.write( "-3t=-12 then divide both sides by -3
\n" ); document.write( "t=4hrs Time R has been riding when V is 7 mi ahead of him
\n" ); document.write( "Check: 4*7=28mi=distance of R
\n" ); document.write( "====3.5*10=35mi=distance of V
\n" ); document.write( "EdJones
\n" ); document.write( "
\n" );