document.write( "Question 1072213: How would you go about finding the solution to this system of three equations in three variables? \r
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document.write( "2x – y + z = 7\r
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document.write( "x + 2y – 5z = -1\r
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document.write( "x – y = 6 \n" );
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Algebra.Com's Answer #687105 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2x – y + z = 7 \n" ); document.write( "x + 2y – 5z = -1 \n" ); document.write( "x – y = 6 \n" ); document.write( "------ \n" ); document.write( "x = 6+y \n" ); document.write( "----- \n" ); document.write( "Substitute for \"x\" in the 1st and the 2nd equation \n" ); document.write( "to get two equations in y and z. \n" ); document.write( "-------------------------------- \n" ); document.write( "12+2y-y+z = 7 \n" ); document.write( "6+y + 2y - 5z = -1 \n" ); document.write( "-------- \n" ); document.write( "y + z = -5 \n" ); document.write( "3y - 5z = -7 \n" ); document.write( "-------- \n" ); document.write( "Modify:: \n" ); document.write( "3y + 3z = -15 \n" ); document.write( "3y - 5z = -7 \n" ); document.write( "------- \n" ); document.write( "Subtract and solve for \"z\": \n" ); document.write( "8z = 8 \n" ); document.write( "z = 1 \n" ); document.write( "---- \n" ); document.write( "Then solve for \"y\". \n" ); document.write( "Then solve for \"x\". \n" ); document.write( "------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------ \n" ); document.write( " |