document.write( "Question 1072191: A metal alloy is 35% copper. Another metal alloy is 50% copper. How much of each alloy should be used to make 600 grams of a metal alloy that is 45% copper? \n" ); document.write( "
Algebra.Com's Answer #687089 by ankor@dixie-net.com(22740)\"\" \"About 
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A metal alloy is 35% copper.
\n" ); document.write( " Another metal alloy is 50% copper.
\n" ); document.write( "How much of each alloy should be used to make 600 grams of a metal alloy that is 45% copper?
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\n" ); document.write( "let x = amt of 50% alloy
\n" ); document.write( "resulting amt is be 600 gr, therefore
\n" ); document.write( "(600-x) = amt of 35% alloy
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\n" ); document.write( "Amt of copper equation
\n" ); document.write( ".50x + .35(600-x) = .45(600)
\n" ); document.write( ".50x + 210 - .35x = 270
\n" ); document.write( ".50x - .35x = 270 - 210
\n" ); document.write( ".15x = 60
\n" ); document.write( "x = 60/.15
\n" ); document.write( "x = 400 gr of 50% alloy required
\n" ); document.write( "then, obviously;
\n" ); document.write( "600-400 = 200 gr of 35% alloy
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\n" ); document.write( "Check this in the original equation
\n" ); document.write( ".50(400) + .35(200) = .45(600)
\n" ); document.write( "200 + 70 = 270 \n" ); document.write( "
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