document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1072205>Question 1072205</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to solve by completeing the square:            ^ :means exponent<BR>\n" );
document.write( "        7x^2 - 14x -56=0 <BR>\n" );
document.write( "I moved 56 to the other side: 7x^2-14x=56<BR>\n" );
document.write( "Then i did (b/2)^2 and got 49 as a third term: 7x^2-14x+49<BR>\n" );
document.write( "I tried to find what added could give me -14 and multiplied could give me 343<BR>\n" );
document.write( "Did i do this wrong? plz help  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #687081 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=687081\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have to divide by the leading coefficient to make it 1, then you can proceed.\r<BR>\n" );
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document.write( "7(x^2-2x)=7(8)<BR>\n" );
document.write( "x^2-2x=8, because both sides are multiplied by 7.<BR>\n" );
document.write( "(x2-2x+1)=8+1<BR>\n" );
document.write( "(x+1)^2=3^2<BR>\n" );
document.write( "(x+1)=+/-3<BR>\n" );
document.write( "x=-1+/- 3<BR>\n" );
document.write( "x=-2, 4<BR>\n" );
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