document.write( "Question 1072074: The perimeter of a rectangle is 50m. If the width were doubled and the length increased by 19, the perimeter would be 108m. What would the width of the rectangle. I need a formula please. \n" ); document.write( "
Algebra.Com's Answer #687039 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! The perimeter of a rectangle is 50m. If the width were doubled and the length increased by 19, the perimeter would be 108m. What would the width of the rectangle. I need a formula please. \n" ); document.write( "——————————————————————————————\r \n" ); document.write( "\n" ); document.write( "There are two formulas:\r \n" ); document.write( "\n" ); document.write( "2L+2W = 50 (1) \n" ); document.write( "and \n" ); document.write( "2(L+19) + 2(2W) = 108 (2) \n" ); document.write( "— \n" ); document.write( "(2) simplifies to 2L+38 + 4W = 108 \n" ); document.write( " 2L + 4W = 70 (2') \n" ); document.write( "— \n" ); document.write( "You can solve for L and W if you need to get their individual values. \n" ); document.write( " |