document.write( "Question 1072115: write a polynomial P with the lowest possible degree that has the given solutions
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document.write( "0,2,1+i,1-i \n" );
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Algebra.Com's Answer #686996 by Edwin McCravy(20086) You can put this solution on YOUR website! \r\n" ); document.write( "\r\n" ); document.write( "x = 0; x = 2; x = 1+1; x = 1-i\r\n" ); document.write( "\r\n" ); document.write( "Get zero on the right, on the last three:\r\n" ); document.write( "\r\n" ); document.write( "x = 0; x-2 = 0; x-1-i = 0; x-1+i = 0\r\n" ); document.write( "\r\n" ); document.write( "Multiply all four left sides together \r\n" ); document.write( "\r\n" ); document.write( "x(x-2)(x-1-i)(x-1+i)\r\n" ); document.write( "\r\n" ); document.write( "and set it equal to all four right sides\r\n" ); document.write( "multiplied together: (0)(0)(0)(0) = 0\r\n" ); document.write( "\r\n" ); document.write( "x(x-2)(x-1-i)(x-1+i) = 0\r\n" ); document.write( "\r\n" ); document.write( "(x²-2x)[(x-1)-i][(x-1+i] = 0\r\n" ); document.write( "\r\n" ); document.write( "(x²-2x)[(x-1)²-i²] = 0\r\n" ); document.write( "\r\n" ); document.write( "(x²-2x)[x²-2x+1-(-1)] = 0\r\n" ); document.write( "\r\n" ); document.write( "(x²-2x)[x²-2x+1+1] = 0\r\n" ); document.write( "\r\n" ); document.write( "(x²-2x)[x²-2x+2] = 0\r\n" ); document.write( "\r\n" ); document.write( "x⁴-2x³+2x²-2x³+4x²-4x = 0\r\n" ); document.write( "\r\n" ); document.write( "x⁴-4x³+6x²-4x = 0\r\n" ); document.write( "\r\n" ); document.write( "P(x) = x⁴-4x³+6x²+4x²-4x\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |