document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=94247>Question 94247</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Train A leaves a station traveling at 48 kilometers per hour. Four hours later, train B leaves the station traveling in the same direction at 68 kilometers per hour. What equation can you use to find the time (t) in hours that it took train B to catch up with train A, and what is the value of t </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #68698 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=68698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d=distance  t=time v=velocity<BR>\n" );
document.write( "d=tv<BR>\n" );
document.write( "Let t=time of 1st train<BR>\n" );
document.write( "Let t-4=time of 2nd train<BR>\n" );
document.write( "for the 1st train d=tv=48t<BR>\n" );
document.write( "for the 2nd train d=tv=68(t-4)<BR>\n" );
document.write( "they both travel the same distance therefore:  48t=68(t-4)<BR>\n" );
document.write( "48t=68t-272<BR>\n" );
document.write( "add 272 and -48t to both sides:  272=20t<BR>\n" );
document.write( "t=13.6hrs<BR>\n" );
document.write( "t-4=9.6hrs time it took train b to catch up to train a<BR>\n" );
document.write( "EdJones </SPAN>\n" );
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