document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1072028>Question 1072028</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A certain culture initially has 25 bacteria and is observed to double every 5 hours.<BR>\n" );
document.write( "A) Find an exponential model n(t) = n02t/a for the number of bacteria in the culture after t<BR>\n" );
document.write( "hours.<BR>\n" );
document.write( "B) Estimate the number of bacteria after 18 hours. Round down the next lower bacterium.<BR>\n" );
document.write( "C) After how many hours will the bacteria count reach 2 million. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #686959 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=686959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A) The exponential model you are looking for would be: n(t)=n&#8320;*2^(t/5),where t is the number of hours after the first 25 bacterium were counted.\r<BR>\n" );
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document.write( "B)n=n&#8320; * 2^(18/5)=25 * 12.125732=303.1433\r<BR>\n" );
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document.write( "C) 2000000=25 * 2^(n/5)<BR>\n" );
document.write( "2^(n/5)=80000<BR>\n" );
document.write( "n/5=16.2877123795<BR>\n" );
document.write( "n=81.4385618977 hours until there a 2 million bacterium. &#9786;&#9786;&#9786;&#9786;<BR>\n" );
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