document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=94247>Question 94247</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Train A leaves a station traveling at 48 kilometers per hour. Four hours later, train B leaves the station traveling in the same direction at 68 kilometers per hour. What equation can you use to find the time (t) in hours that it took train B to catch up with train A, and what is the value of t </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #68693 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=68693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 48T=68(T-4)<BR>\n" );
document.write( "48T=68T-272<BR>\n" );
document.write( "68T-48T=272<BR>\n" );
document.write( "20T=272<BR>\n" );
document.write( "T=272/20<BR>\n" );
document.write( "T=13.6 HOURS THE FAST TRAIN WILL CATCH THE SLOWER TRAIN.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "48*13.6=68(13.6-4)<BR>\n" );
document.write( "652.8=68*9.6<BR>\n" );
document.write( "652.8=652.8<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );