document.write( "Question 1071963: the half life of carbon14 is 5730 years.\r
\n" ); document.write( "\n" ); document.write( "A.) f(t)=ae^(-kt) solve for k\r
\n" ); document.write( "\n" ); document.write( "b.) if the bone is 65% of the original amount of carbon14. how old is the bone in years?\r
\n" ); document.write( "\n" ); document.write( "c.) If a bone is known to be 1900 years old, what percent of the original Carbon14 is remaining in the bone. Round to the nearest percent.
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Algebra.Com's Answer #686857 by josgarithmetic(39623)\"\" \"About 
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A:
\n" ); document.write( "Find k, given half-life 5730 years.
\n" ); document.write( "\"1%2F2=1%2Ae%5E%28k%2A5730%29\"\r
\n" ); document.write( "\n" ); document.write( "\"ln%281%2F2%29=ln%28e%5E%28k%2A5730%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"ln%281%2F2%29=5730%2Ak\"\r
\n" ); document.write( "\n" ); document.write( "\"k=ln%281%2F2%29%2F5730\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28k=-0.000121%29\"\r
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\n" ); document.write( "\n" ); document.write( "B:
\n" ); document.write( "How old is bone if 65% of original C-14 remains?
\n" ); document.write( "\"0.65=1%2Ae%5E%28-0.000121%2At%29\"\r
\n" ); document.write( "\n" ); document.write( "\"ln%280.65%29=ln%28e%5E%28-0.000121t%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"-0.000121t=ln%280.65%29\"\r
\n" ); document.write( "\n" ); document.write( "\"t=ln%280.65%29%2F%28-0.000121%29\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28t=3560%29\", years
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