document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1071958>Question 1071958</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is a+(a-2)=(a+3)-(a+1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #686855 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=686855\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a+(a-2)=(a+3)-(a+1) <BR>\n" );
document.write( "= a+a-2 = a+3-(a+1)<BR>\n" );
document.write( "= 2a-2 = a+3+((-1)a-1)Note: nothing changed here, the -1 stands for -a. When you multiply the -1 using the distributive properties of multiplication, your get:<BR>\n" );
document.write( "-1*a and -1*-1 = -1a and +1, or simply -a+1. Let's continue. Remove unnecessary parenthesis:<BR>\n" );
document.write( "= 2a-2 = a+3+(-1)a-1 Add 3 and -1<BR>\n" );
document.write( "= 2a-2 = a+2+(-1)a Now a-1a = 0, let's rewrite:<BR>\n" );
document.write( "= 2a-2 = 2<BR>\n" );
document.write( "= 2a-2-(-2) = 2-(-2)<BR>\n" );
document.write( "= 2a = 2+2<BR>\n" );
document.write( "= 2a = 4<BR>\n" );
document.write( "= a = 4/2<BR>\n" );
document.write( "= a = 2<BR>\n" );
document.write( "----------------------<BR>\n" );
document.write( "Check, see if I got an equality:<BR>\n" );
document.write( "a+(a-2)=(a+3)-(a+1)<BR>\n" );
document.write( "2+(2-2) = (2+3)-(2+1)<BR>\n" );
document.write( "2 = 5-3; 2 = 2 Correct\r<BR>\n" );
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