document.write( "Question 94351: find the number of permutations of the first 8 letters of the alphabet for each situation. taking 3 letters at a time \n" ); document.write( "
Algebra.Com's Answer #68679 by jim_thompson5910(35256)    ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since order does matter (this is because the word \"cab\" is different than \"abc\"), we can use the permutation formula:\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Expand 8! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Expand 5! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So 8 choose 3 (where order does matter) yields 336 unique combinations\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "  |