document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1071828>Question 1071828</A>: <I><SPAN STYLE=\"word-break: break-all;\">  If 1/7*(1/a-1/b) = (a-b)*(1/-5) <BR>\n" );
document.write( "where a>b>0. What is the value of (a)(b)?\r<BR>\n" );
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document.write( "Please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #686772 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=686772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  1/7*(1/a-1/b) = (a-b)*(1/-5) <BR>\n" );
document.write( "(b-a)/ab=(a-b)(-7/5), multiplying through and putting the fraction over a common denominator.<BR>\n" );
document.write( "Now multiply both sides by -1.<BR>\n" );
document.write( "(b-a)(-1)=(a-b), which you want<BR>\n" );
document.write( "(a-b)/ab=(a-b)(7/5)<BR>\n" );
document.write( "cancel the (a-b)<BR>\n" );
document.write( "(1/ab)=(7/5)<BR>\n" );
document.write( "ab=5/7 by inverting both sides </SPAN>\n" );
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