document.write( "Question 94340: ``Hi, I need help with the problem:
\n" );
document.write( " 3+ (1 + 2^3)^2\r
\n" );
document.write( "\n" );
document.write( "I keep getting different answers. When I worked it I got 68, but when I used my calculator it said 84. When I worked it, I squared the 1 and got 1 and squared the 2^3 and got 2^6. Then I added 1 to the 64 (2^6) and got 65. Then I added 3 and got 68. I know how the caluclator got 84, but the way I learned it you are supposed to multiple by the 2 first. If you could help me that would be great.\r
\n" );
document.write( "\n" );
document.write( "Thanks \n" );
document.write( "
Algebra.Com's Answer #68672 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 3+ (1 + 2^3)^2 \n" ); document.write( "= 3 + (1+8)^2 \n" ); document.write( "= 3 + 9^2 \n" ); document.write( "= 84 \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |